N order to set rates, an insurance company is trying to estimate the number of sick days that full time workers at an auto repair shop take per year. Assume σ = 6.8 days. How large a sample must be selected if the company wants to be 98% confident that the true mean differs from the sample mean by no more than 2 days?

The  large  sample must be selected if the company wants to be 98% confident that the true mean differs from the sample mean by no more than 2 days

n = 62.5427≅63

Step-by-step explanation:

Step1:-

Given maximum of error = M.E =  2 days

Given population standard deviation  σ = 6.8 days

98% confident level Z₀.₀₂ = 2.326

Step2:-

we know that the maximum of error

cross multiplication , we get

squaring on both sides, we get

on calculation , we get

n = 62.5427

Conclusion:-

The  large  sample must be selected if the company wants to be 98% confident that the true mean differs from the sample mean by no more than 2 days

n = 62.5427≅63

p> q if you calculate p is100 q is 79

30 units^2

step-by-step explanation:

area is l × w

the length is 3

and the width is 10

3 × 10= 30 units squared