Suppose the sediment density (g/cm3 ) of a randomly selected specimen from a certain region is known to have a mean of 2.80 and standard deviation of 0.85. If a random sample of 35 specimens is selected, what is the probability that the sample average sediment density is at most 3.00?

0.918 is the probability that the sample average sediment density is at most 3.00

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 2.80

Standard Deviation, σ = 0.85

Sample size,n = 35

We are given that the distribution of sediment density is a bell shaped distribution that is a normal distribution.

Formula:

Standard error due to sampling:

P(sample average sediment density is at most 3.00)

Calculation the value from standard normal z table, we have,  

0.918 is the probability that the sample average sediment density is at most 3.00

answer: c

because if you look at the chart you can see a pattern and compare it to the question he simplify out your

but i think the formula is f(x)=6x