---WILL GIVE BRAINLIEST---
A portion of the graph of f(x) = −x2 + 6x − 5 is shown. Which of the following describes all solutions for f(x)? a partial parabola opening down and passing through 1 comma 0 and 5 comma zero with endpoints at 0 comma negative 5 and 6 comma negative 5

Options:
A) (x, y) for all real numbers
B) (x, −x2 + 6x − 5) where 0 ≤ x ≤ 6
C) (x, −x2 + 6x − 5) where 1 ≤ x ≤ 5
D) (x, y) where 1 ≤ x ≤ 5

answer: i would say b

step-by-step explanation:

with the way the question is worded, i believe b is the answer

the cost of the apple depends on the weight

1

step-by-step explanation:

it's the only multiple of both and the least

good job you smart son of a gun you are smarter that einstein. 7

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.