What are the foci of the hyperbola whose equation is

(-6, 2) and (14, 2)
(-4, 2) and (12,2)
(4,-8) and (4, 12)
(4,-6) and (4, 10)

(4,12) (4,-8)

Step-by-step explanation:

you can find the distance from the foci to the center of a hyperbola using the formula c2 = a2 + b2.

in this equation we have both a and b, so substitute the values into the equation...

c2 = 64 + 36

c2 = 100

square root

c=10

therefore the distance from the foci from the center is 10 units.

since the equation has the y term first, the transverse axis is vertical. so 10 y  units from the center which is (4,2) is (4,12) and (4,-8)

making the answer be (4,12) and (4,-8).

Hope this helped :)

yx = 36

step-by-step explanation:

cos f = opposite side/ hypotenuse

cos f = yw / yx

we know cos f = 4/9 and yw =16

4/9 = 16/yx

multiply each side by yx

4/9 yx = 16/ yx * yx

4/9 yx = 16

multiply each side by 9/4

9/4 * 4/9 yx = 16 *9/4

yx = 36