The bottom of a rectangular swimming pool has a perimeter of 60 meters and an area of 209 square meters. What are the dimensions of the pool?

Width = 11, Length = 19 m.

Step-by-step explanation:

Let the width be w and the length be l.

The perimeter = 60 , so:

2w + 2l = 60 A.

The area = 209, so:

wl = 209B.

From equation A:

w = (60 - 2l)/2

w = 30 - l

Substitute for  w in equation B:

l(30 - l) = 209

30l - l^2 = 209

l^2 - 30l + 209 = 0

l = 19 , 11.

Substitute l = 19 in equation A:

w = 30 - 19 = 11.

the answer is y = 11.54

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