The length of a rectangular pool is to be four times its width and a sidewalk 6ft wide will surround the pool. If a total area of 1600 square feet has been set aside for the area of the pool and the sidewalk, what are the dimensions of the pool?

52 feet by 13 feet.

Step-by-step explanation:

Given:

The length of a rectangular pool is to be four times its width.

Sidewalk is 6 feet wide will surround the pool.

If a total area of 1600 square feet has been set aside for the area of the pool and the sidewalk.

Question asked:

What are the dimensions of the pool?

Solution:

Let width of a rectangular pool =

Then the length of a rectangular pool will be =

Combined length of pool and the sidewalk = length of pool + width of sidewalk + width of sidewalk

Combined length of pool and the sidewalk =

Similarly, Combined width of pool and the sidewalk =

Combined area of pool and the sidewalk = 1600

Subtracting both sides by 144

Since dimensions can never be in negative, hence

Width of a rectangular pool = = 13 feet

The length of a rectangular pool will be = =

Therefore, the dimensions of the pool are 52 feet by 13 feet.

the red lines denote the population of the bacteria after 35 hours. that would be 2,409.24. the y-intercept is the blue line which is 800 because that is the starting point. the equation used to make the graph is 800(1.032)^h, where h is the number of hours.

step-by-step explanation:

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step-by-step explanation: