The average diameter of sand dollars on a certain island is 4.00 centimeters with a standard deviation of 0.60 centimeters. If 16 sand dollars are chosen at random for a collection, find the probability that the average diameter of those sand dollars is more than 3.85 centimeters. Assume that the variable is normally distributed.

0.8413 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 4.00 centimeters

Standard Deviation, σ = 0.60 centimeters

Sample size, n = 16

We are given that the distribution of average diameter is a bell shaped distribution that is a normal distribution.

Formula:

Standard error due to sampling =

P(diameter of sample is more than 3.85 centimeter)

P(x > 3.85)

Calculation the value from standard normal z table, we have,  

0.8413 is the probability that the  the average diameter of sample of 16 sand dollars is more than 3.85 centimeters.

answer: i believe it’s 245.04

step-by-step explanation:

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)