A study conducted by the American Skincare Organization found that, 38% of beachgoers wear sunblock and 65% of beachgoers wear sunglasses. Additionally, they found that 39% of beachgoers wear sunglasses and do not wear sunblock.

a. Define the events.
b. Write down the given probabilities.
c. What is the probability that a beachgoer does not wear sunglasses

Events: 1. Wearing sunblock (and no glasses?)

            2. Wearing sunglasses (and sunblock?)

            3. Wearing sunglasses and no sunblock

Probabilities: 1. 19/50, or 38%

                      2. 13/20, or 65%

                      3. 39/100, or 39%

Probability of not wearing sunglasses: 19/50, or 38%

Problem with this question: the percentages add up to much over 100%. If I have worked out this question wrong, please comment and I will fix it.

Step-by-step explanation:

Events:

Events are the possibilities, and the three events listed are: wearing sunblock, wearing sunglasses, and wearing sunglasses and no sunblock.

Probabilities:

38/100 simplifies to 19/50 when both sides are divided by 2

65/100 simplifies to 13/20 when both sides are divided by 5

39/100 cannot be simplified

Probability:

Assuming that group one does not wear sunglasses (because it is not listed if they do or do not wear sunglasses), we have that 38% of people do not wear sunglasses.

In conclusion, we get that 19/50 people do not wear sunglasses.

77

step-by-step explanation:

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation: