Parker drove a total distance of 4 and 1 over 2 miles during the months of june and july. if parker only drove 1 over 8 of a mile every day, which expression shows the number of days he went driving?
4 and 1 over 2 ⋅ 1 over 8
4 and 1 over 2 + 1 over 8
4 and 1 over 2 ÷ 1 over 8
4 and 1 over 2 – 1 over 8

4 and 1 over 2 ÷ 1 over 8

Step-by-step explanation:

Given that : Total distance drove by Parker =4 and 1 over 2 miles= miles

Distance drove by Parker each day = 1 over 8 mile= mile

To find the total number of days , we need to divide the total distance by the distance drove by him in each day.

Thus, the number of days he went driving=4 and 1 over 2 ÷ 1 over 8

The expression that represents the number of days he went driving is:

                          4 and 1 over 2 ÷ 1 over 8

The total distance traveled by Parker in the month of June and July is:

                   4 and 1 over 2 miles i.e.

Also, the distance traveled by Parker each day is:

                      1 over 8 miles i.e.

The number of days he went driving is:

Ratio of the total distance to distance traveled each day.

i.e.

Number of days is:  

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v