A basketball player has made 6060% of his foul shots during the season. Assume the shots are independent.
a) What's the expected number of shots until he misses?
b) If the player shoots 99 foul shots in the fourth quarter, how many shots do you expect him to make?
c) What is the standard deviation of the 99 shots

a) 2.5 shots

b) 59.4 shots

c) 4.87 shots

Step-by-step explanation:

Probability of making the shot = 0.6

Probability of missing the shot = 0.4

a) The expected number of shots until the player misses is given by:

The expected number of shots until the first miss is 2.5

b) The expected number of shots made in 99 attempts is:

He is expected to make 59.4 shots

c) Let "p" be the proportion shots that the player make, the standard deviation for n = 99 shots is:

The standard deviation is 4.87 shots.

sorry, i can't understand your question. will later if you describe more clearly!

: )

i am thinking c. sorry if im wrong .

step-by-step explanation: