Suppose you need to find a quadratic function that has x-intercepts at
x = 0
and
x = 2
and a maximum value of 3.
(a)
A function in standard form that has parameters
a =
and
k =

has a maximum value of 3.
(b)
To obtain intercepts that are separated by 2 units, change the value of a from part (a) to
a =

(c)
To shift the x-intercepts to
x = 0
and
x = 2,
set
h
to
h =

(d)
Then, in the standard form equation of the quadratic function, the values of the parameters that meet the given criteria are
a
=
h
=
k
=
(e)
In the expanded form equation of the quadratic function, the values of the parameters that meet the given criteria are
a
=
b
=
c
=

answer: i'm not going to give you the answer, but some hints to work it out.

step-by-step explanation: so, if there is a straight line that means that the line angle is 180°. so we subtract the 2 angle measures provided, (15 and 38) from 180. so the answer is 180 - (38 + 15). (you have to solve the equation)

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

3

step-by-step explanation: