When the Olympic Games were held outside Mexico City in 1968, there was much discussion about the effect the high altitude (7340 feet) would have on the athletes. Assuming air pressure decays exponentially by 0.4% every 100 feet, by what percentage is air pressure reduced by moving from sea level to Mexico City?

By moving from sea level to Mexico City  air pressure is reduced by 25%.

Step-by-step explanation:

Hi, to answer this we have to apply a decrease rate formula

P0 (1-r)^x

Where:  

p0= initial pressure

r = decrease rate. (0.4 = 0.4/100=0.004 decimal form)

x = feet (hundredths, since the air pressure decays every 100 feet we have to divide the input value by 100)

Replacing with the values given

P0 (1- 0.4/100)^(7340/100) =

P0 (0.996)^73.4 =

P0 ( 0.75)=

The air pressure at Mexico City compared to the sea level is 75% (0.75 x 100 =75%)

To obtain the percent decrease  

100% -75% =25%

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )