In a sample of 60 adults selected randomly from one town, it is found that 12 of them have been exposed to a particular strain of the flu. The test statistic is z=1.08. Find the P-value for a test of the claim that the proportion of all adults in the town that have been exposed to this strain of the flu is different to 15% (H1: p ≠0.15 ).

Step-by-step explanation:

Data given and notation

n=60 represent the random sample taken

X=12 represent the adults exposed to a particular strain of the flu

estimated proportion of adults exposed to a particular strain of the flu

is the value that we want to test

represent the significance level

z would represent the statistic (variable of interest)

represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is 0.15 or no.:  

Null hypothesis:  

Alternative hypothesis:  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

(1)  

The One-Sample Proportion Test is used to assess whether a population proportion is significantly different from a hypothesized value .

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

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step-by-step explanation: