Chris Paul is shooting free throws. Making or missing free throws doesn't change the probability that he will make his next one, and he makes his free throws 88% of the time.
What is the probability of Chris Paul making all of his next 9 free throws attempts.
A) 9.088
B) 0.88^9
C) (1-0.88)^9
D) 9×(1-0.88)

B; 0.88^9

Step-by-step explanation:

in this question, we are tasked with calculating the probability that Chris Paul makes all of his 9 free throws.

Firstly, we write the probability of scoring a free throw. From the question, this was given to be 88% and that is 88/100 = 0.88

now , to calculate the probability of making the next nine, what to do is to multiply the probability by itself in a total of 9 time

This is ;

0.88 * 0.88 * 0.88 * 0.88 * 0.88 * 0.88 * 0.88 * 0.88 * 0.88 = 0.88^9

0.88^9 is the correct answer.

Step-by-step explanation:

3=log(n)=2

answer a: product property

option 1

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