A random sample of 64 SAT scores of students applying for merit scholarships showed an average of 1400 with a standard deviation of 240.
If we want to provide a 95% confidence interval for the SAT scores, the degrees of freedom for reading the critical values of "t" statistic is:.

Degree of freedom = 63

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 64

Sample mean = 1400

Sample standard deviation = 240

We need to make a 95% confidence interval.

We use the t-statistic for the same.

Degree of freedom:

Degree of freedom  for reading the critical values of t-statistic is

Thus, the degree of freedom is 63.

10.416 meters per second

step-by-step explanation:

distance=1 00 meters

time= 9.6 seconds in decimal form or 9 3/5 as a mixed number

average speed= 100/9.6

=10.416 meters per second or 10 52/125 as a mixed number.

the correct answer is $7.38

step-by-step explanation: