f(x) = x2 + 2x - 2
Show graph

Step-by-step explanation:

f(x) = x2 + 2x - 2  should be rewritten using " ^ " to indicate exponentiation:

f(x) = x^2 + 2x - 2.

We find a couple of key points and use the fact that this parabola is symmetric about the line

          -2

x = ----------- = -1.  When x = -1, y = f(-1) = (-1)^2 + 2(-1) - 2, or 1 - 2 -2, or -3.

        2(1)

Thus the vertex is at (-1, -3).  The y-intercept is found by letting x = 0:  y = -2.  The axis of symmetry is x = -1.

Graph x = -1 and then reflect this y-intercept (0, -2) about the line x = -1, obtaining (-2, -2).  If necessary, find 1 or two more points (such as the x-intercepts).

To find the roots (x-intercepts), set f(x) = x^2 + 2x - 2 = 0 and solve for x.

Completing the square, we obtain x^2 + 2x + 1 - 2 = + 1, or (x + 1)^2 = 3.

Taking the square root of both sides yields x + 1 = ±√3.  One of the two roots is x = 1.732 - 1, or 0.732, so one of the two x-intercepts is (0.732, 0).

answer: 2/4

step-by-step explanation:

the image is given below

since the options are not given so we draw it from the equation

the given equation is

y = (x-1) (x+4)

y = y² + 3x - 4

the above equation is a quadratic equation which will have two roots. if we draw the graph for it, it will look like this