The endpoints of directed line segment PQ have coordinates of P(-7,5) and Q(5,3). What are the coordinates of point A, on PQ, that divide PQ into a ratio of 1:3?

Correction

P(-7,-5)

d(-4,-3)

Step-by-step explanation:

-Given the coordinates of PQ as  P(-7,5) and Q(5,3).

-The sum of the ratios is:

Let d be the point that divide's the segment in the ratio 1:3

#The coordinates that divide the segment into a 1:3 ratio therefore has to be from P.

#We determine the length of the x-axis coordinate:

#We determine the length of the y-axis coordinate:

Hence, the coordinates of point d is d(-4,-3)

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

think about it deeply and passionately about this property

i am sorry