Given that sinθ=8/17 , what is cosθ ? Enter your answer, as a simplified fraction, in the boxes.

Cosθ = 15/17

Step-by-step explanation:

Sinθ = 8/17

We know that,

Sin^2 θ + cos^2 θ =1

64/289 + cos^2 θ =1

1 - 64/289 = cos^2 θ

225/289 = cos^2 θ

Cos θ = √225/289

Cos θ = 15/17

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐