QuestionDetails:
coroner's rule of thumb
coroners estimate time of death using the rule of thumb that abody cools about 2 degrees farenheit during the first hour afterdeath and about 1 degree farenheit for each additional hour. assuming an air temperature of 68 degrees farenheit and a livingbody temperature of 98.6 degrees farenheit, the temperature T(t) indegrees farenheit of a body at a time t hours since death is givenby:
T(t) = 68 +30.6e^-kt
For what value of k will the body cool by 2 degrees farenheitin the first hour?
ResponseDetails:
Assuming that T(1) = 98.6 - 2 = 96.6 we get:

ResponseDetails:
since k = 0.067
b) using the value of k, after how many hours will thetemperature of the body be decreasing at a rate of 1 degree F perhour?**
**iplugged in 0.067, but i'm not sure of my answer. below iswhat i did for the second question:
96.6= 68 + 30.6e^ -0.067t
28.6= 30.6e^ -0.067t
0.935= e^ -0.067t
ln0.935 = -0.067t ln e
1= t
c) using the value of k, show that, 24 hours afer death, the coroner's rule of thumb gives approximately the sametemperature as the formula.

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