If the value of b decreases, but the value of m remains the same, what will happen to the x-intercept?

A) The x-intercept decreases.

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  

Consider the function f(x) = mx + b, where m > 0.

If the value of b decreases, but the value of m remains the same, what will happen to the x-intercept?

A) The x-intercept decreases.

B) The x-intercept increases.

C) The x-intercept approaches zero.

D) The x-intercept remains the same

Here is my

Given the function f(x) = mx + b, where m > 0.

x-intercept happen when y =0

When b decreases and m stay the same, the value of f(x) will be decreased. For example:  f(x)= 2x + 3 = 0

When  b unchanged, m unchanged we have: 2x + 3 = 0 <=> x = -3/2

When  b decreases to 2, m unchanged we have: 2x + 2 = 0 <=> x = -1

Obviously that,  -1 < -3/2 so the x-intercept will be decreased

b. the decimal could be two-tenths.

step-by-step explanation:

what statement? is there an image?