Mathematics, 15.04.2020 18:46 Zgt

Women athletes at the a certain university have a long-term graduation rate of 67%. Over the past several years, a random sample of 38 women athletes at the school showed that 22 eventually graduated. Does this indicate that the population proportion of women athletes who graduate from the university is now less than 67%? Use a 10% level of significance.

Answers: 2

Show answers

Answers

Answer from: Anliz0179

$z=\frac{0.579 -0.67}{\sqrt{\frac{0.67(1-0.67)}{38}}}=-1.193$

p_v =P(z

So the p value obtained was a very high value and using the significance level given $\alpha=0.1$ we have $p_v\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that the proportion of women athletes graduated is not significantly lower than 0.67 or 67% at 10% of significance

Step-by-step explanation:

Data given and notation

n=38 represent the random sample taken

X=22 represent the number of women athletes graduated

$\hat p=\frac{22}{38}=0.579$ estimated proportion of women athletes graduated

p_o=0.67 is the value that we want to test

$\alpha=0.1$ represent the significance level

Confidence=90% or 0.90

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is lower than 0.67 or no:

Null hypothesis: $p \geq 0.67$

Alternative hypothesis: p < 0.67

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value p_o .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.579 -0.67}{\sqrt{\frac{0.67(1-0.67)}{38}}}=-1.193$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.1$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

p_v =P(z

Answer from: Quest

step-by-step explanation:

Answer from: Quest

step-by-step explanation:

6.48/4 4 goes into 6.48 1.62 times

Another question on Mathematics

Mathematics, 21.06.2019 14:30

Which of these people has balanced their checkbook correctly? oa. gary: the balance in his check register is $500 and the balance in his bank statement is $500. b. gail: the balance in her check register is $400 and the balance in her bank statement is $500. c. gavin: the balance in his check register is $500 and the balance in his bank statement is $510.

Answers: 2

Answer

Mathematics, 21.06.2019 15:40

Is it true that product of 3 consecutive natural numbers is always divisible by 6? justifyyour answer

Answers: 2

Answer

Mathematics, 21.06.2019 16:40

If 24 people have the flu out of 360 people, how many would have the flu out of 900. choose many ways you could use proportion that david would use to solve this problem

Answers: 1

Answer

Mathematics, 21.06.2019 19:00

[15 points, algebra 2]simplify the complex fraction and find the restrictions.

Answers: 1

Answer

You know the right answer?

Women athletes at the a certain university have a long-term graduation rate of 67%. Over the past se...

Questions