Mathematics, 15.04.2020 19:25 Gabby1128
Given ΔBUG as shown with B(-3,-1), U(-3,3) and G(4,1). Find the area of triangle BUG.
Answers: 2
![Area = \frac{1}{2} [x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)]](/tpl/images/0602/3377/eb648.png)
Let,
![Area = \frac{1}{2} [-3(3 - 1) + (-3)(1 - (-1)) + 4(-1 - 3)]\\\\Area = \frac{1}{2} [-3(2) + (-3)(2) + 4(-4)]\\\\Area = \frac{1}{2} [-6 + (-6) + (-16)}\\\\Area = \frac{1}{2} [-6 - 6 -16]\\\\Area = \frac{1}{2} [-28]\\\\\mathbf{Area = 14 sq. units}](/tpl/images/0602/3377/c01c0.png)
![A=\frac{1}{2} [x_{1} (y_{2} - y_{3} ) + x_{2} ( y_{3} - y_{1} )+x_{3} (y_{1} - y_{2} )]](/tpl/images/0602/3377/8f4a1.png)
..............(1)
, 
and 
are the coordinates of triangle![A=\frac{1}{2} [ -3(3-1)+(3)(1-(-1))+4(-1-3)]](/tpl/images/0602/3377/5a685.png)
![=\frac{1}{2} [ -3(2)+(3)(1+1)+4(-4)]](/tpl/images/0602/3377/56283.png)
![=\frac{1}{2} [ -6 -6 - 16 ]](/tpl/images/0602/3377/827b3.png)
![=\frac{1}{2} [ -28 ]](/tpl/images/0602/3377/5e829.png)
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Given ΔBUG as shown with B(-3,-1), U(-3,3) and G(4,1). Find the area of triangle BUG....
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