Dolores is flying an airplane and is descending at a 8° angle towards a runway. If she can see a warehouse behind her at a 65° angle that is 400 meters away from the runway, how much further does she have to fly until she lands? Round to the nearest tenth.

Using the Sine rule, the distance left to fly before hitting the runway would be 379.1 meters

Taking the distance to runway as D :

Using the Sine rule :

(400/ Sin(107)°) / (D/sin(65)°)

Cross multiply :

D × sin(107)° = 400 × sin(65)°

D × 0.9563047 = 362.52311

Divide both sides by 0.9563047

D = 362.52311 / 0.9563047

D = 379.087 meters

Therefore, the distance left till she lands is 379.1 meters

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379.1 meters

Step-by-step explanation:

To understand better the problem, we can see the image attached.

We can form a triangle, where the angle in the airplane is (180 - 65 - 8) = 107 degrees, the angle in the warehouse is 65 degrees, and the angle in the runway is 8 degrees.

The distance between the warehouse and the runway is 400 meters, so to find the distance from the airplane to the runway, we can use the law os sines:

400 / sin(107) = D / sin(65)

D = 400 * sin(65) / sin(107) = 379.1 meters

i dont know

step-by-step explanation:

umm. i dont know

c) the median for town a 30" is greater than the median for town b 25"

step-by-step explanation:

town a, median = q2 = 30

town b, median - q2 = 25

so the median for town a 30" is greater than the median for town b 25"