The Ming family has a backyard kiddie pool with the dimensions shown. After a lot of splashing one afternoon, the pool is only half full. What is the volume of water remaining in the pool? Either enter an exact answer in terms of \piπpi or use 3.143.143, point, 14 for \piπpi.

The volume of water remaining in the pool is 91,696.2 in³

Step-by-step explanation:

Assumption: Inflated internal dimensions (Diameter x  Height):, 103 in  x 22 in,

Given the dimensions, we note that the volume of water in the pool can be found with the relation for finding the volume of a cylinder which is;

Volume of a cylinder = Area of base × Height

Since the base of the circular pool has a diameter of 103 in, therefore, the ares of base is given by

Area of circle = π × r² where r = radius of the circle = D/2 = 103/2 = 51.5 in

Therefore area of base = π·r² = 3.143×51.5² = 8336.02 in²

∴ Volume of pool = 8336.02 in² × Height =  8336.02 in² × 22 in = 183,392.4785 in³

The half full pool is then = 183,392.4785 in³× 0.5 = 91,696.2 in³

The volume of water remaining in the pool = 91,696.2 in³.

Step-by-step explanation:

16 pie

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1

a) 0

step-by-step explanation:

i^413 x i^0 = 0 as any number multiplied by a zero is

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