What happens to the value of the expression 1+3f1+3f1, plus, 3, f as fff increases? Choose 1 Choose 1 (Choice A) A It increases. (Choice B) B It decreases. (Choice C) C It stays the same.

A. It Increases

Step-by-step explanation:

Given the expression:

1+3f

When f=1, 1+3f=1+3(1)=1+3=4

When f=2, 1+3f=1+3(2)=1+6=7

When f=3, 1+3f=1+3(3)=1+9=10

We can see that the value of the given expression for each successive term increases and in fact form the sequence

4,7,10,...

Therefore, when f increases, 1+3f increases.

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

yess

step-by-step explanation:

idk whyy this is happening, i cant even read my notification bc i keep getting errors

~coco