The area of a circular base of the larger cylinder is 81π. The area of a circular base of the smaller cylinder is 9π.

Make a conjecture about the similar solids. How is the scale factor and the ratio of the surface areas related? Check all that apply.

- The dimensions of the larger cylinder are 3 times the dimensions of the smaller cylinder.
- The surface area of the larger cylinder is 32, or 9, times the surface area of the smaller cylinder.
- If proportional dimensional changes are made to a solid figure, then the surface area will change by the square of the scale factor of similar solids.

A & C

The dimensions of the larger cylinder are 3 times the dimensions of the smaller cylinder.

If proportional dimensional changes are made to a solid figure, then the surface area will change by the square of the scale factor of similar solids.

Step-by-step explanation:

answer: the answer is (b) amie should have multiplied

step-by-step explanation: given a sphere and a cylinder with same radius and height.

let, 'r' be the radius of the cylinder and sphere and 'h' be the height of the cylinder. according to the question,

r = h.

now, the volume of the sphere will be

and the volume of the cylinder will be

therefore, we have

thus, ammie should have multiplied the volume of the sphere