Find the derivative g(x)=ln(2x^2+1)

4x / (2x^2+1)

Step-by-step explanation:

g(x)=ln(2x^2+1)

Using u substitution

u= 2x^2 +1

du = 4x  dx

g'(x) = d/du ( g(u) du)

We know that the derivative of ln(u) = 1/u  since this is always positive

        = 1/ u* du

 Substituting x back into the equation

g'(x) = 1/(2x^2+1) * 4x

       = 4x / (2x^2+1)

sure i'm up for it

step-by-step explanation:

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %