The smallest of the three circles with center D has a radius

of 8 inches and

CB = BA= 4 inches.

What is the sum of the areas of all three circles?

80 pi in.2

96 Pi in. 2

208 pi in. 2

464 pi in.2

464π in²

Step-by-step explanation:

The smallest circle has a radius of 8 in.

The middle circle has a radius of 8 + 4 = 12 in.

The largest circle has a radius of 12 + 4 = 16 in.

So the sum of the areas is:

π (8 in)² + π (12 in)² + π (16 in)²

= 64π in² + 144π in² + 256π in²

= 464π in²

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