An article reports that 1 in 500 people carry the defective gene that causes inherited colon cancer. In a sample of 2000 individuals, what is the approximate distribution of the number who carry this gene? We can approximate this distribution by the Poisson distribution with μ = . (a) Use the Poisson approximation to calculate the approximate probability that between 4 and 9 (inclusive) carry the gene. (Round your answer to three decimal places.) (b) Use the Poisson approximation to calculate the approximate probability that at least 9 carry the gene. (Round your answer to three decimal places.)

a) P=0.558

b) P=0.021

Step-by-step explanation:

We can model this random variable as a Poisson distribution with parameter λ=1/500*2000=4.

The approximate distribution of the number who carry this gene in a sample of 2000 individuals is:

a) We can calculate that the approximate probability that between 4 and 9 (inclusive) as:

b) The approximate probability that at least 9 carry the gene is:

u rich

step-by-step explanation:

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^