How much would you need to deposit in an account now in order to have $4000 in the account in 10 years? Assume the account earns 5.3% interest compounded weekly.

  $2355.06

Step-by-step explanation:

Use the compound interest formula, filling in the numbers you know. Then solve for the number you don't know.

  A = P(1 +r/n)^(nt)

where A is the account balance, P is the amount invested, r is the annual rate, n is the number of times per year interest is compounded, and t is the number of years.

Filling in the given values, we have ...

  4000 = P(1 +.053/52)^(52·10) = P(1.6984738)

  P = 4000/1.6984738 ≈ 2355.06

You would need to deposit $2355.06 in order to have $4000 in 10 years.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

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step-by-step explanation:

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