Mathematics, 16.04.2020 03:59 madiliann12120
A random sample of 18 size aa batteries for toys yield a mean of 3.74 hours with standard deviation, 0.63 hours. (a) find value of t (the multiplier) that would be used to create a 99% ci. t = (b) find the margin of error for a 99% ci.
Answers: 1
![1 - \frac{1 - 0.99}{2} = 0.995([tex]t_{.995}](/tpl/images/0604/5561/e0671.png)
). So we have T = 2.8982. This is the answer for a.Another question on Mathematics
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A random sample of 18 size aa batteries for toys yield a mean of 3.74 hours with standard deviation,...
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