What are the foci of the hyperbola whose equation is (x-6)^2/16-(y+7)^2/9= 1?

The foci of the hyperbola is (0,3) and (0,-3).

Step-by-step explanation:

Given,

The equation of the hyperbola:

To find the foci of the given parabola

Formula

If the equation of the hyperbola:  

The focus will be (0,±c) where c² = a²+b²

Now,

Here, a=3 and b=4

c² = 3²+4² = 25

or, c = ±5

Hence,

The foci of the hyperbola is (0,3) and (0,-3)

divide the numbers

step-by-step explanation: