Really need help with my trigonometry math homework!! Anything would help :)

14) The horizontal distance when the plane is at 500 ft. is 2358.5 ft.

15) The length of the wire is 44.7 ft.

Step-by-step explanation:

14) Let the horizontal distance be 'd'

the height of the plane = 500 ft.

Angle of elevation= 12°

tan 12° = 500/d

d = 500/tan12°

d = 500/0.212

d = 2358.5 foot

The horizontal distance when the plane is at 500 ft. is 2358.5 ft.

15) Let the length of the wire be 'n'

The height of the pole = 30ft.

Angle formed between pole and wire = 48°

Cos 48° = 30/n

n = 30/cos 48°

n = 30/ 0.67

n =  44.7 ft.

The length of the wire is 44.7 ft.

e^-kt = n/n0 = 0.79  

-kt = ln 0.79  

t = - ln 0.79/0.0001  

= 2357 years

step-by-step explanation:

step-by-step explanation:

what was your answer?