What is f(5) if f(1) = 3.2 and f(x + 1) = Five-halves(f(x))?

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Step-by-step explanation:

i just answered the question. ed2020

Step-by-step explanation:

then f(2) = f(2-1) - 5 = f(1) - 5 = 2 - 5 = -3

thenf(3) = f(3-1) - 5 = f(2) - 5 = -3 - 5 = -8

then f(4) = f(4-1) - 5 = f(3) - 5 = -8 - 5 = -13

then f(5) = f(5-1) - 5 = f(4) - 5 = -13 -5 = -18

then f(6) = f(6-1) - 5 = f(5) - 5 = -18 -5 = -23

goog may have it for you

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.