If 10 friends are going to occupy 10 seats in shuttle on the way to the airport, how many different ways can they arrange themselves in the shuttle?

3,628,800 ways can they arrange themselves in the shuttle, If 10 friends are going to occupy 10 seats in shuttle on the way to the airport.

Step-by-step explanation:

The given is,

                   10 friends are going to occupy 10 seats in shuttle on the way to the airport  

Step:1

                   No. of friends - 10

                   No.of seats in space shuttle - 10

                   Formula to calculate the no. of ways to arrange,

                                       ............................(1)

                    Where, n - Positive integer

Step:2

                  From given, n = 10                  

                  Equation (1) becomes,

                                            = 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1

                                            = 3628800

                                            = 3628800 ways

Result:

                3,628,800 ways can they arrange themselves in the shuttle, If 10 friends are going to occupy 10 seats in shuttle on the way to the airport.

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation: