On a recent administration of a state bar exam, 22% of the test takers passed the test, 78% of those who passed were first-time test takers, and 60% of those who failed were first-time test takers. What percent of first-time test takers passed the test

Step-by-step explanation:

%17 because you take %78 of %22

(the second part is more tricky...

17% were first time takers who past.

%60  of %78 = %46.8 = percentage of people who were first time takers who failed.

so total percentage of first time takers = 46.8 +17 = %63.8.

Then 17/63.8 X %100 = percent of first time takers who passed.

=26.6 percent therefore %27 is correct.

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3

a = 3.14

b = 18

c = 18/5 or 3.6 or 3 3/5

step-by-step explanation: