Jacob randomly draws two cards from a standard deck of 52 cards. he does not replace the first card. what is the probability that both cards are kings?
a. 1/663
b. 1/1326
c. 1/221
d. 1/26

During the first draw, Jacob has 4 out of 52 chances of drawing a King since there are 4 Kings and 52 cards in total. However on the second draw, Jacob will only have 3 out of 51 chances of drawing a King since he won't place the first card back.

The equation will be:
X = (4/52) * (3/51), where X is the probability that both cards are Kings
X = 1/221

The answer would be C. 1/221

Ithink it is 7. 16

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.