Please help me out this is algebra and I have to show work thank you

Width = 8m

Length = 24m

Step-by-step explanation:

LW = 192

L = 2W + 8

(2W + 8) * W = 192

2W² + 8W -192 = 0

W² + 4W - 96 = 0

(W - 8) ( w + 12) = 0     width is positive

W = 8

L = 24

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.