Let f(z) = u(x, y) +iv(x, y) is continuous on a closed bounded region R and f is analytic and not constant in the interior of R. Prove that the component function u(x, y) has a maximum and minimum values of v(x, y) are reached on the boundary of R and never in the interior.

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.

a precentage of 6th graders. the population is all 6th graders. let me know if i'm wrong, i hope this ! : )

step-by-step explanation:

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~batmans wife dun dun