Which point lies on the line described by the equation below? y + 3 = 2(x - 1)
a. (2, 9)
b. (1, -4)
c. (1, 7)
d. (-1, -7)
e. (0, 0)
f. (2, 1)

Option D is correct.

(-1, -7)

Step-by-step explanation:

Given the equation of line:           ......[1]

A.

(2, 9)

Substitute the value of x = 2 and y = 9 in [1]; we have;

  False.

Similarly, for

B.

(1, -4)

Substitute the value of x = 1 and y = -4 in [1]; we have;

  False.

C.

(1, 7)

Substitute the value of x = 1 and y = 7 in [1]; we have;

  False.

D.

(-1, -7)

Substitute the value of x = -1 and y = -7 in [1]; we have;

        True

E.

(0,0)

Substitute the value of x = 0 and y = 0 in [1]; we have;

  False.

F.

(2, 1)

Substitute the value of x = 2 and y = 1 in [1]; we have;

  False.

Therefore, the only point which lies on the line described by the equation  is, (-1, -7)

hi how are you doing today? if you ever need just tell me

step-by-step explanation:

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4