G A researcher wants to construct a 95% confidence interval for the proportion of children aged 8-10 living in Atlanta who own a cell phone. Estimate the sample size needed if no estimate of p is available so that the confidence interval will have a margin of error of 0.02.

The sample size needed is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue of .

The margin of error of the interval is:

95% confidence level

So , z is the value of Z that has a pvalue of , so .

Estimate the sample size needed if no estimate of p is available so that the confidence interval will have a margin of error of 0.02.

We have to find n, for which M = 0.02.

There is no estimate of p available, so we use

The sample size needed is 2401.

70

step-by-step explanation:

40 x 50 = 2000

step-by-step explanation: