Ucsd reddit A watermelon is thrown down from the 7th floor of Urey Hall at UCSD. If the initial height of the watermelon is 21.0 meters, and it is thrown straight downward with an initial downward velocity of 3.00 m/s. How far will the watermelon have fallen from its starting height after 1.50 seconds?

15.525 feet

Step-by-step explanation:

GIVEN: A watermelon is thrown down from the floor of Urey Hall at UCSD. If the initial height of the watermelon is , and it is thrown straight downward with an initial downward velocity of .

TO FIND: How far will the watermelon have fallen from its starting height after seconds.

SOLUTION:

initial height of watermelon

initial velocity of watermelon

acceleration due to gravity

According to newton's law of motion

when seconds

Hence watermelon will have fallen 15.525 feet from its starting height after 1.5 seconds

first option

a function is a relation in which an input is paired with exactly one output.

so, let's find the right answer.

in our first option, our inputs are january, february, and march. the outputs are 30, 28, and 25. each input has it's own output. this is correct!

our second option we know is incorrect, because ms. valverade has two outputs, dogs and cats. this is not a function.

our third option is incorrect as well. the yellow square has two ouputs, the square and the triangle.

lastly, in our fourth option, we see the number 7 two times with a different output. therefore, this is not a function.

remember: each input must be paired with only one output!

answer for #1 is c

answer for #2 is d

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