Indicate the equation of the line, in standard form, that passes through (2, -4) and has a slope of 3/5. Enter your answer into the blank equation box. a0

-3/5x + y = - 26/5

Step-by-step explanation:

First, I put everything in slope-intercept form, just because it's more simple for me.

y = 3/5x + b

Since we don't have b, we can use the coordinate they give us to solve for it.

-4 = 3/5 (2) + b

-26/5 = b

y = 3/5x - 26/5

Now, we can move the variables around to fit the form:

Ax + By = C

-3/5x + y = - 26/5

I hope this helped!

jwjwkwkwkkkdjebd b jdjejdndj he jenej

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)