Enter in standard form the equation of the line passing through the given point and having the given slope.. b(2, - 5), m = -2/3

Y = mx + b
slope(m) = -2/3
(2,-5)...x = 2 and y = -5
now we sub, we r looking for b, the y int
-5 = -2/3(2) + b
-5 = - 4/3 + b
-5 + 4/3 = b
- 15/3 + 4/3 = b
- 11/3 = b

equation is : y = -2/3x - 11/3...but we need it in standard form
Ax + By = C

y = -2/3x - 11/3
2/3x + y = - 11/3multiply by 3
2x + 3y = -11 <== standard form