What is the value of x?
(geometry question)

Given:

The interior angles of the triangle are 44°, 3t - 45° and x - 15°

The exterior angle of the triangle is 4t - 29°

We need to determine the value of x.

Value of t:

The value of t can be determined using the exterior angle theorem.

Applying the theorem, we have;

Thus, the value of t is 28.

Value of x:

The exterior angle 4t -29 and the interior angle x - 15 are linear pairs.

Since, linear pairs add up to 180°, we have;

Substituting t = 28, we get;

Thus, the value of x is 112.

225x²+4=0

225x²=0-4

225x²=-4

x²=-4/225

x=±√-4/225