A bowl contains 4 tangerines and 5 clementines. John randomly selects one piece of fruit, and then Pam randomly selects one of the remaining pieces of fruit. What is the probability that John selects a tangerine and Pam selects a clementine?

5/18

Step-by-step explanation:

There are 9 pieces of fruit in the bowl,  tangerines and 5 clementines.

Assuming that they do not put the fruit back

P (tangerine) = number of tangerines/ total = 4/9

Then John keeps his and there are  8 pieces of fruit in the bowl,  

3 tangerines and 5 clementines.

P (Clementine) = number of clementines/ total = 5/8

P (tangerine, no replacement, Clementine) = P (tangerine) * P (Clementine)

                                                                        = 4/9 * 5/8 =5/18

10/60

step-by-step explanation:

if you divide 10 by 60 the answer is 0.166666 while if you divide or solve the other problems it equals 0.6