The parabola y=x^2-2x+4 will have a vertex of

The vertex is at (h, k) => (1, 3)

Step-by-step explanation:

Complete the square of y=x^2 - 2x + 4 to determine the coordinates of the vertex.

Note that the first two terms of y=x^2 - 2x + 4 resemble the perfect square (x - 1)^2:

y=x^2 - 2x + 4 => y= ( x^2 - 2x + 1 )+ 4 - 1, or

                            y = (x - 1)^2 + 3

Comparing this last result to the standard equation y = (x - h)^2 + k, we see that h = 1 and k = 3.  The vertex is at (h, k) => (1, 3)

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol

0

step-by-step explanation:

equals the constant of proportionality.

solve for