Teniendo en cuenta que tg 45°=1, deduce el valor de sen 45° y de cos 45° mediante las relaciones fundamentales.

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

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step-by-step explanation:

$450 is the answer.

step-by-step explanation:

30% of 450 = 135

450-135=315