A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find out the time at which the rocket will reach its max, to the nearest 100th of a second. y=-16x^2+128x+136

The rocket will reach its max after 4 seconds

Step-by-step explanation:

Hi, to find the maximum height, we have to set the first derivative of the equation equal to zero.

y=-16x^2+128x+136

0 = (2)-16x +128  

0= -32x+128

Solving for x:

32x = 128

x = 128/32

x = 4 seconds

The rocket will reach its max after 4 seconds

Feel free to ask for more if needed or if you did not understand something.

they can both be solutions depends on the equation

step-by-step explanation:

what is the equation? ?

lo98765432wqasdfghjkloi87654567890

step-by-step explanation: