What is the probability of a die landing on an even number on the first toss, and then an odd number on the second toss?
Dice- 6 sides

Please help

1/4 chance

Step-by-step explanation:

Number of even numbers on a die-3

Number of odd numbers on a die-3

a die has 6 sides,

therefore

1/2 of the numbers on a die are even and 1/2 are odd

so a 3/6 chance (1/2 chance (simplify)) of landing on an even number on the first roll

And  a 3/6 chance (1/2 chance (simplify)) of landing on an odd number on the second roll

Multiply the two together and a 9/36 chance of this event or simplified to a 1/4 chance of this event

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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